9.28x^2-25x-125=0

Solution for 9.28x^2-25x-125=0 equation:

9.28x^2-25x-125=0

a = 9.28; b = -25; c = -125;
Δ = b2-4ac
Δ = -252-4·9.28·(-125)
Δ = 5265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5265}=\sqrt{81*65}=\sqrt{81}*\sqrt{65}=9\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-9\sqrt{65}}{2*9.28}=\frac{25-9\sqrt{65}}{18.56}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+9\sqrt{65}}{2*9.28}=\frac{25+9\sqrt{65}}{18.56}
$